Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining.
Example 1:
Input: height = [0,1,0,2,1,0,1,3,2,1,2,1]
Output: 6
Explanation: The above elevation map (black section) is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped.
Example 2:
Input: height = [4,2,0,3,2,5]
Output: 9
Constraints:
n == height.length
0 <= n <= 3 * 10^4
0 <= height[i] <= 10^5
Solution
class Solution {
public:
int trap(vector<int>& height) {
int i = 0;
int j = height.size() - 1;
int maxleft = 0, maxright = 0;
int res = 0;
while(i < j) {
if(height[i] <= height[j]) {
if (height[i] > maxleft) maxleft = height[i];
else res += (maxleft - height[i]);
i++;
} else {
if (height[j] > maxright) maxright = height[j];
else res += (maxright - height[j]);
j--;
}
}
return res;
}
};