# LeetCode 1833. Maximum Ice Cream Bars

It is a sweltering summer day, and a boy wants to buy some ice cream bars.

At the store, there are `n` ice cream bars. You are given an array `costs` of length `n`, where `costs[i]` is the price of the `ith` ice cream bar in coins. The boy initially has `coins` coins to spend, and he wants to buy as many ice cream bars as possible. 

Return *the **maximum** number of ice cream bars the boy can buy with* `coins` *coins.*

**Note:** The boy can buy the ice cream bars in any order.

**Example 1:**

```
Input: costs = [1,3,2,4,1], coins = 7
Output: 4
Explanation: The boy can buy ice cream bars at indices 0,1,2,4 for a total price of 1 + 3 + 2 + 1 = 7.
```

**Example 2:**

```
Input: costs = [10,6,8,7,7,8], coins = 5
Output: 0
Explanation: The boy cannot afford any of the ice cream bars.
```

**Example 3:**

```
Input: costs = [1,6,3,1,2,5], coins = 20
Output: 6
Explanation: The boy can buy all the ice cream bars for a total price of 1 + 6 + 3 + 1 + 2 + 5 = 18.
```

**Constraints:**

* `costs.length == n`
* `1 <= n <= 10^5`
* `1 <= costs[i] <= 10^5`
* `1 <= coins <= 10^8`

## Solution

```
class Solution {
public:
    int maxIceCream(vector<int>& costs, int coins) {
        sort(begin(costs), end(costs));
        int num = 0;
        for (int cost : costs) {
            if (coins >= cost) {
                num++;
                coins -= cost;
            } else {
                break;
            }
        }
        return num;
    }
};
```


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