LeetCode 1676. Lowest Common Ancestor of a Binary Tree IV
Tree
Given the root
of a binary tree and an array of TreeNode
objects nodes
, return the lowest common ancestor (LCA) of all the nodes in nodes
. All the nodes will exist in the tree, and all values of the tree's nodes are unique.
Extending the definition of LCA on Wikipedia: "The lowest common ancestor of n
nodes p1
, p2
, ..., pn
in a binary tree T
is the lowest node that has every pi
as a descendant (where we allow a node to be a descendant of itself) for every valid i
". A descendant of a node x
is a node y
that is on the path from node x
to some leaf node.
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], nodes = [4,7]
Output: 2
Explanation: The lowest common ancestor of nodes 4 and 7 is node 2.
Example 2:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], nodes = [1]
Output: 1
Explanation: The lowest common ancestor of a single node is the node itself.
Example 3:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], nodes = [7,6,2,4]
Output: 5
Explanation: The lowest common ancestor of the nodes 7, 6, 2, and 4 is node 5.
Example 4:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], nodes = [0,1,2,3,4,5,6,7,8]
Output: 3
Explanation: The lowest common ancestor of all the nodes is the root node.
Constraints:
The number of nodes in the tree is in the range
[1, 104]
.-109 <= Node.val <= 109
All
Node.val
are unique.All
nodes[i]
will exist in the tree.All
nodes[i]
are distinct.
Solution
class Solution {
TreeNode* lowestCommonAncestor(TreeNode* root, const set<TreeNode*>& nodes_set) {
if (root == nullptr) {
return nullptr;
}
if (nodes_set.count(root) > 0) {
return root;
}
TreeNode* l = lowestCommonAncestor(root->left, nodes_set);
TreeNode* r = lowestCommonAncestor(root->right, nodes_set);
if (l && r) {
return root;
}
return l ? l : r;
}
public:
TreeNode* lowestCommonAncestor(TreeNode* root, vector<TreeNode*> &nodes) {
set<TreeNode*>nodes_set(nodes.begin(), nodes.end());
return lowestCommonAncestor(root, nodes_set);
}
};
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